There was a math problem I did at one point where I came up with this: If a+b=c where a is not equal to 0 and b is not equal to 0, then 1/a+1/b=c/ab.

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# Inverse Addition

Thoughts from a Thinker, Programmer, and Outdoorsman

There was a math problem I did at one point where I came up with this: If a+b=c where a is not equal to 0 and b is not equal to 0, then 1/a+1/b=c/ab.